Bash Palindrome Rearranging
palindrome_rearranging() {
    local _s=$1
    local -A _val
    local _i _c
    for ((_i = 0; _i < ${#_s}; _i++)); do
        _c=${_s:_i:1}
        _val[$_c]=$(( ${_val[$_c]:-0} + 1 ))
    done
    local _odd=0
    for _c in "${!_val[@]}"; do
        (( _val[$_c] % 2 != 0 )) && ((_odd++))
    done
    if (( _odd <= 1 )); then echo true; else echo false; fi
}

This counts character frequency and checks whether the string has the right number of odd counts to form a palindrome.